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# Se Dau N Numere Naturale Nenule. Ordonați Descrescător Cele N Numere După Numărul Lor De Divizori.

Given a set of non-zero natural numbers, it can be difficult to determine which one has the highest number of divisors. Fortunately, there is an easy way to determine the order of the numbers according to the number of divisors they have. In this article, we will discuss how to sort natural numbers in descending order by their number of divisors.

## Sorting Natural Numbers by Number of Divisors

The process of sorting natural numbers by their number of divisors is relatively simple. First, count the number of divisors each number has. Then, arrange the numbers in descending order based on the number of divisors each number has. If two numbers have the same number of divisors, then the number with the highest value should be listed first.

For example, given the following set of natural numbers: 4, 6, 8, 10, 12, the divisor count for each number is as follows: 4 has 2 divisors, 6 has 4 divisors, 8 has 4 divisors, 10 has 4 divisors, and 12 has 6 divisors. Therefore, the numbers should be arranged in descending order of divisor counts, which is 12, 6, 8, 10, 4.

## Descending Order of Divisor Counts

Once the numbers are arranged in descending order of divisor counts, the next step is to determine the order of the numbers within the same divisor count. The number with the highest value should be listed first, followed by the number with the second highest value, and so on.

For example, given the following set of natural numbers: 2, 6, 8, 10, 12, the divisor count for each number is as follows: 2 has 1 divisor, 6 has 4 divisors, 8 has 4 divisors, 10 has 4 divisors, and 12 has 6 divisors. Therefore, the numbers should be arranged in descending order of divisor counts, which is 12, 8, 10, 6, 2.

In summary, sorting natural numbers by their number of divisors is a relatively straightforward process. First, count the number of divisors each number has. Then, arrange the numbers in descending order based on the number of divisors each number has. Finally, if two numbers have the same number of divisors, the number with the highest value should be listed first. With these simple steps, you can quickly

If you have been assigned to order a set of natural numbers (i.e. 0, 1, 2, 3 and so on) from the highest to the lowest depending on the number of their divisors, then this article is just what you need! In this text, we will discuss the easiest way to do this and provide clear instructions to help you do the ordering correctly.

The number of divisors of a given natural number can be calculated by determining all of its factors. Put simply, if we are given a number 12, then its divisors will be 1, 2, 3, 4, 6 and 12. In order to order our natural numbers descending by the number of their divisors, we must rearrange them in the same way we would if we were multiplying them together.

Once we have arranged the numbers from highest to lowest, we can begin to order the numbers from highest to lowest by the number of their divisors. To do this, we must find the divisors for each number, starting with the highest number. For each divisor, count how many times it appears when the number is written as a product of prime numbers. The highest number to have the highest number of divisors is the one that we will place first in the descending order. Afterward, move down the list and repeat the same process for each number.

For example, let us take the natural numbers 4, 8, 12 and 18 and order them according to the number of their divisors. 4 = 2², so it has three divisors (1, 2, and 4). 8 = 2³, so it has four divisors (1, 2, 4 and 8). 12 = 2² x 3, so it has six divisors (1, 2, 3, 4, 6 and 12). 18 = 2 x 3², so it has six divisors (1, 2, 3, 6, 9, and 18). Therefore, the descending order of our natural numbers by the number of their divisors will be 12, 18, 8, and 4.

We have discussed the simplest way to order a set of natural numbers from highest to the lowest depending on the number of their divisors. To do this, you must rearrange the numbers, find the divisors for each of them and count how many times they appear when the number is written as a product of prime numbers. Lastly, order the numbers from the highest to the lowest according to the number of their divisors.